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BEE 2010 Question Paper with Answers — Paper-1

General Aspects of Energy Management & Energy Audit
Available here with full solutions — 52 questions recovered from the 2010 exam:
Objective (1 mark)47 of 50
Short (5 marks)5 of 8
Long (10 marks)0 of 6
This is not the complete paper. The questions below are the ones we could recover and verify; the rest of that year’s paper is not reproduced here. Every answer shown is checked against the 2014 BEE guidebook and carries its book section reference and an explanation.

Full paper pattern: Section-I 50×1 = 50 marks · Section-II 8×5 = 40 · Section-III 6×10 = 60 · Total 150, pass mark 75, 3 hours.
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Objective questions (1 mark) — 47

📖 §3.1 Energy types & forms — potential (stored) vs kinetic energy

1. The type of energy possessed by the charged capacitor is

  1. kinetic energy
  2. electrostatic
  3. potential
  4. magnetic
Answer: B) electrostatic
Confirmed vs Book-1 §3.1 — A charged capacitor stores energy in the electrostatic field between its plates. (Answer not marked in source.). Book-1 Ch.3, Energy types & forms — potential (stored) vs kinetic energy.
📖 §8.3 CPM — benefits

2. PERT/CPM provides which of the following benefits

  1. predicts the time required to complete the project
  2. shows activities which are critical to maintaining the schedule
  3. graphical view of the project
  4. all the above
Answer: D) all the above
Confirmed vs Book-1 §8.3 — Book-1 lists the CPM/PERT benefits as: gives a graphical view of the project; predicts the time required to complete the project; shows which activities are critical to maintaining the schedule and which are not. All three options are therefore correct → (d) all the above.
📖 §1.7 Indian Energy Scenario — Electrical Energy Supply (Table 1.12)

3. What is the present share of thermal power in the total installed power generating capacity in India?

  1. about 65%
  2. about 50%
  3. less than 45%
  4. about 18%
Answer: A) about 65%
Confirmed vs Book-1 §1.7 — Table 1.12 gives total thermal capacity as 1,63,305 MW out of 2,38,743 MW installed, i.e. 68.4%. Of the four choices, 'about 65%' is the only one in that range. 'About 50%' corresponds roughly to coal alone (58.9%) and 18% is close to hydro (16.84%), so both are wrong.
📖 §10.1 Energy and environment

4. Which one of the following is not an example of air pollution from boilers and furnaces?

  1. sulphur dioxide (SO2)
  2. chloro-fluro carbons (CFC)
  3. nitrous oxide (NOX)
  4. carbon monoxide (CO)
Answer: B) chloro-fluro carbons (CFC)
Confirmed vs Book-1 §10.1 — The principal emissions from fuel combustion in boilers and furnaces are CO2, particulate matter, SOx, NOx, hydrocarbons and CO. CFCs are man-made refrigerants/propellants (§10.5) and are not a product of combustion.
📖 §10.5 Greenhouse gases & GWP (Table 10.1)

5. Select the one with the highest Global warming potential among the following gases

  1. carbon dioxide
  2. methane
  3. sulphur hexafluoride
  4. nitrous oxide
Answer: C) sulphur hexafluoride
Confirmed vs Book-1 §10.5 — The book states 'Sulfur hexafluoride is the most potent greenhouse gas'; Table 10.1 gives GWP: CO2 = 1, CH4 = 23, N2O = 300, SF6 = 22,000. SF6 therefore has the highest GWP. (Note: PFC has the LONGEST life, 50,000 yrs, but a lower GWP of 5700.)
📖 §3.4 Latent heat of fusion / vaporization — Qₗ = m · h

6. The heat required to change a substance from liquid to vapor state without change of temperature is termed as

  1. latent heat of fusion
  2. latent heat of vaporization
  3. heat capacity
  4. sensible heat
Answer: B) latent heat of vaporization
Confirmed vs Book-1 §3.4 — Liquid-to-vapour phase change at constant temperature absorbs the latent heat of vaporization. (Answer not marked in source.). Book-1 Ch.3, Latent heat of fusion / vaporization — Qₗ = m · h.
📖 §9.6 Specific Energy Consumption (Figs 9.7-9.8)

7. The ratio of energy consumption to corresponding production quantity is called

  1. energy performance
  2. specific energy consumption
  3. production factor
  4. specific production ratio
Answer: B) specific energy consumption
Confirmed vs Book-1 §9.6 — Specific Energy Consumption (SEC) = energy consumed / corresponding production (e.g. kWh/tonne, toe/tonne). 'Production factor' is current output ÷ reference output, and 'energy performance' is the % improvement figure - neither is energy per unit output. Answer (b).
📖 §10.10 Kyoto mechanisms — CDM

8. CDM stands for

  1. carbon depletion mechanism
  2. clean development mechanism
  3. clear development mechanism
  4. carbon depletion machinery
Answer: B) clean development mechanism
Confirmed vs Book-1 §10.10 — CDM = Clean Development Mechanism, one of the three Kyoto flexibility mechanisms (with Emissions Trading and Joint Implementation). It lets an Annex-I country implement an emission-reduction project in a developing country and earn CERs.
📖 §3.4 Calorific value — GCV vs NCV (bomb calorimeter)

9. The difference between GCV and NCV of coal is

  1. the heat of vaporization of the moisture and atomic hydrogen (conversion to water vapor) in the fuel
  2. the difference in heat released by using theoretical air and allowable excess air
  3. difference in accounting the un-burnt content in the ash
  4. none of the above
Answer: A) the heat of vaporization of the moisture and atomic hydrogen (conversion to water vapor) in the fuel
Confirmed vs Book-1 §3.4 — GCV minus NCV equals the latent heat of the water formed from fuel moisture and hydrogen. (Answer not marked in source.). Book-1 Ch.3, Calorific value — GCV vs NCV (bomb calorimeter).
📖 §4.1 Definition and Objectives of Energy Management (Book EOC Objective Q3)

10. The objective of energy management includes

  1. minimising energy costs
  2. minimising waste
  3. mitigating environmental degradation caused by energy
  4. all the above
Answer: D) all the above
Confirmed vs Book-1 §4.1 — Book §4.1 lists three objectives: optimum energy procurement and utilisation, minimising energy costs/waste without affecting production and quality, and minimising environmental effects. Since (a), (b) and (c) are each one of those listed objectives, only 'all the above' is complete.
📖 §4.12 Energy audit instruments — Fyrite

11. The instrument used to measure CO2 from boiler stack is

  1. infrared thermometer
  2. fyrite
  3. anemometer
  4. pitot tube
Answer: B) fyrite
Confirmed vs Book-1 §4.12 — Book §4.12: in the Fyrite a hand bellows pump draws flue gas into an absorbing solution — potassium hydroxide (dyed red) for CO2, chromous chloride (blue) for O2 — and the liquid-volume change reads the gas percentage. An infrared thermometer reads surface temperature, an anemometer air velocity and a pitot tube duct pressure/velocity, so none of them measures CO2.
📖 §4.11 Fuel and Energy Substitution

12. Replacement of steam based hot water generation by solar water heating system is an example of

  1. matching energy usage to the requirement
  2. maximising system efficiency
  3. energy substitution
  4. performance improvement
Answer: C) energy substitution
Confirmed vs Book-1 §4.11 — Book §4.11 gives exactly this example under 'few examples of energy substitution': "Replacement of steam based hot water by solar systems." It is not matching usage to requirement (§4.8, e.g. impeller trimming) nor maximising system efficiency (§4.9, e.g. steam traps) — the energy SOURCE itself is changed.
📖 §4.4 Step 6 Analysis of energy use / energy balance (Sankey detail in Book-1 Ch5 & Ch9)

13. Which among the following statements is not applicable in the case of Sankey diagram?

  1. useful tool to represent entire input and output energy flow
  2. represents visually, various outputs and losses
  3. depicts rejection and wastage of material flow
  4. helps energy managers to focus on finding improvements in a prioritized manner
Answer: C) depicts rejection and wastage of material flow
Confirmed vs Book-1 §4.4 — A Sankey diagram is an ENERGY flow diagram: band widths show the input energy and each output and loss stream, letting the energy manager prioritise the biggest losses. It does not depict rejection and wastage of MATERIAL flow — that belongs to the process flow diagram / material balance, so (c) is the statement that does not apply.
📖 § 2.3.6 Designated Consumers — 9 notified industries

14. Which of the following sectors is not a designated consumer as per the Energy Conservation Act, 2001?

  1. textile
  2. paper and pulp
  3. glass
  4. chlor alkali
Answer: C) glass
Confirmed vs Book-1 §2.3.6 — Glass is not among the nine notified energy-intensive industries. Textile (3,000 MTOE/yr), Pulp & Paper (30,000) and Chlor-Alkali (12,000) are all notified designated-consumer sectors, so only 'glass' can be the answer.
📖 §7.3 Financial Analysis Techniques — Simple Payback Period

15. A waste heat recovery system costs Rs. 54 lakh and Rs. 2 lakh per year to operate and maintain. If the annual savings is Rs. 20 lakhs, the payback period will be

  1. 8 years
  2. 2.7 years
  3. 3 years
  4. 10 years
Answer: C) 3 years
Confirmed vs Book-1 §7.3 — Simple payback = Capital cost / ANNUAL NET savings, and net savings = yearly benefit - yearly O&M cost. Net savings = 20 - 2 = Rs.18 lakh/yr; Payback = 54 / 18 = 3 years. (Dividing by the gross 20 lakh gives the trap answer 2.7 yr.)
📖 §10.11 CDM — host country approval (DNA)

16. Which is the Designated National Agency (DNA) of India for CDM?

  1. Ministry of Environment and Forests (MoEF)
  2. Central Pollution Control Board (CPCB)
  3. State Designated Agency (SDA)
  4. Bureau of Energy Efficiency (BEE)
Answer: A) Ministry of Environment and Forests (MoEF)
Confirmed vs Book-1 §10.11 — The book states 'National CDM Authority in India is Ministry of Environment & Forest (MoE&F)'. The DNA evaluates and approves CDM projects against the host country's sustainable-development criteria and is the point of contact. BEE and CPCB have no CDM approval role.
📖 §9.6 CUSUM Charts (Fig 9.12)

17. A CUSUM graph follows a random fluctuation trend and oscillates around

  1. 50% line
  2. 100% line
  3. 0 line
  4. mean value line
Answer: C) 0 line
Confirmed vs Book-1 §9.6 — 'A typical CUSUM graph follows a trend and shows random fluctuation of energy consumption and oscillation around zero (baseline or standard).' CUSUM = running Σ(E_actual - E_calculated); when only random variation exists the positive and negative differences cancel, so the plot hovers about the 0 line. Answer (c).
📖 §3.5 MTOE conversions — 1 toe = 10⁷ kcal, 1 kWh = 860 kcal

18. The calorific value of coal is 4,200 kCal/kg. Find out the oil equivalent of 1000 kg of coal if the calorific value of oil is 10,000 kCal/kg

  1. 42,000 kg
  2. 96 kg
  3. 420 kg
  4. 128 kg
Answer: C) 420 kg
Confirmed vs Book-1 §3.5 — Oil equivalent = (1000 x 4200)/10000 = 420 kg. (Answer not marked in source.). Book-1 Ch.3, MTOE conversions — 1 toe = 10⁷ kcal, 1 kWh = 860 kcal.
📖 §9.4 Benefits of M&T

19. The goal of using energy monitoring and targeting (M&T) is to

  1. determine the relationship of energy use to key performance indicators such as production, rejects etc.
  2. identify and explain increase in energy cost
  3. draw energy consumption trends (weekly, seasonal, operational)
  4. accomplish all the above
Answer: D) accomplish all the above
Confirmed vs Book-1 §9.4 (Benefits of M&T) — the listed benefits include relating energy use to key output/performance indicators, identifying and explaining an increase or decrease in energy use, and drawing energy consumption trends (weekly, seasonal, operational). All three are stated goals, so 'all the above'. Answer (d).
📖 §4.12 Energy audit instruments — Ultrasonic Flow Meter

20. A non-contact method to measure the water flow through a metallic pipe is

  1. orifice meter
  2. turbine flow meter
  3. ultrasonic flow meter
  4. none of the above
Answer: C) ultrasonic flow meter
Confirmed vs Book-1 §4.12 — Book §4.12 describes the ultrasonic flow meter as the popular means of NON-contact flow measurement, with clamp-on transducers working through the metallic pipe wall. An orifice meter needs a plate inside the line and a turbine meter a rotor in the stream, so both are contact/intrusive; 'none of the above' is therefore wrong.
📖 §4.3 Need for Energy Audit

21. To identify the energy conservation opportunity in a plant, the best option is to carry out:

  1. energy audit
  2. training and awareness programme
  3. seminars and workshops
  4. analysis of the plant energy bills
Answer: A) energy audit
Confirmed vs Book-1 §4.3 — Book §4.3: the energy audit "will help to understand more about the ways energy is used ... and help in identifying the areas where waste can occur and where scope for improvement exists" — it is the translation of conservation ideas into realities. Training, seminars and bill analysis alone build awareness or give only macro data; bill analysis is merely one input to the preliminary audit.
📖 §7.3 Financial Analysis Techniques — Return on Investment (ROI)

22. The ratio of annual net cash flow to capital cost is ____

  1. net present value
  2. internal rate of return
  3. return on investment
  4. discount factor
Answer: C) return on investment
Confirmed vs Book-1 §7.3 — Book: 'ROI expresses the annual return expected from a project as a percentage of capital cost.' ROI = annual net cash flow / capital cost. NPV and IRR are discounted measures and the discount factor is 1/(1+k)^n, so only ROI matches the stated ratio.
📖 §3.3 Motor loads & motor loading — Examples 3.8 / 3.9 (nameplate kW = OUTPUT)

23. Name plate kW rating of an induction motor indicates

  1. input kW to the motor
  2. output kW of the motor
  3. minimum input kW to the motor
  4. maximum input kW to the motor
Answer: B) output kW of the motor
Confirmed vs Book-1 §3.3 — Motor nameplate kW is the rated shaft (output) power. (Answer not marked in source.). Book-1 Ch.3, Motor loads & motor loading — Examples 3.8 / 3.9 (nameplate kW = OUTPUT).
📖 §3.3 Electricity basics — maximum demand / load factor (tariff in kVA)

24. Normally the maximum demand is charged for

  1. kWh
  2. kWAh
  3. kVA
  4. kVArh
Answer: C) kVA
Confirmed vs Book-1 §3.3 — Maximum demand is billed in kVA. (Answer not marked in source.). Book-1 Ch.3, Electricity basics — maximum demand / load factor (tariff in kVA).
📖 §9.6 Linear Regression — E = C + M·P

25. The fixed energy consumption of a company is 1000 kWh per month. The line slope of the energy (y) versus production (x) chart is 0.3. The energy consumed in kWh per month for a production level of 80,000 tons/month is

  1. 24,000
  2. 24,100
  3. 25,000
  4. 38,000
Answer: C) 25,000
Corrected (was b) — Book-1 §9.6: E = M·P + C with M = slope = 0.3 and C = fixed = 1,000 kWh/month. E = 0.3 × 80,000 + 1,000 = 24,000 + 1,000 = 25,000 kWh/month. Option (b) 24,100 wrongly adds 100 instead of the 1,000 kWh fixed load; the variable part alone (24,000) is option (a). Answer (c) 25,000.
📖 §3.3 Example 3.6 — resistive load power varies as V²

26. For an electric heater, voltage remaining constant, the heat output ___ when resistance decreases.

  1. decreases
  2. increases
  3. first increases then decreases
  4. remains same
Answer: B) increases
Confirmed vs Book-1 §3.3 — P = V^2/R, so at constant V, lower R gives higher heat output. (Answer not marked in source.). Book-1 Ch.3, Example 3.6 — resistive load power varies as V².
📖 §3.3 Power, Voltage & Current — 3-phase P = √3·Vₗ·Iₗ·cosφ

27. The active power consumption of AC 3-phase motive drive is determined by using which one of the following relations.

  1. sqrt3 x V x I
  2. sqrt3 x V^2 x I x Cosφ
  3. 3 x V x I x Cosφ
  4. sqrt3 x V x I x Cosφ
Answer: D) sqrt3 x V x I x CosO
Confirmed vs Book-1 §3.3 — Three-phase active power = sqrt3 x V x I x cos(phi). (Answer not marked in source.). Book-1 Ch.3, Power, Voltage & Current — 3-phase P = √3·Vₗ·Iₗ·cosφ.
📖 §4.12 Energy audit instruments — Manometer with Pitot Tube

28. Air velocity in ducts can be measured by using ___

  1. pyrometer
  2. bourdon gauge
  3. pitot tube and manometer
  4. anemometer
Answer: C) pitot tube and manometer
Confirmed vs Book-1 §4.12 — Book §4.12: "To measure pressure in air pipes, manometers must be used in combination with a pitot tube" — the velocity pressure so obtained gives duct air velocity. An anemometer measures air velocity too but is not among the Ch4 instruments, while a pyrometer reads high temperature and a Bourdon gauge static pressure only.
📖 §7.3 Financial Analysis Techniques — Return on Investment (ROI)

29. For a project to be viable, the ROI must always be ___ the interest rate.

  1. lower than
  2. higher than
  3. equal to
  4. no relation to
Answer: B) higher than
Confirmed vs Book-1 §7.3 — Book: 'ROI must always be higher than cost of money (interest rate) so as to make the project attractive; the greater the return on investment the better.' If ROI were below the borrowing rate the project would destroy value.
📖 §8.3 Gantt chart

30. The simplest technique for scheduling of tasks and tracking progress is

  1. CPM
  2. Gantt chart
  3. PERT
  4. CUSUM
Answer: B) Gantt chart
Confirmed vs Book-1 §8.3 — Book-1: Gantt's scheduling tool is a horizontal bar graph 'commonly used for scheduling the tasks and tracking the progress of energy management projects'. It is the simplest such tool; CPM/PERT are the more advanced network methods and CUSUM is a monitoring & targeting technique. Option (b).
📖 §10.1 Energy and environment / §10.5 CO2 from fuels

31. Changing from furnace oil firing to natural gas firing will result in

  1. increased CO2 emissions
  2. decreased SO2 emissions
  3. decreased % of wet flue gas loss
  4. none of the above
Answer: B) decreased SO2 emissions
Confirmed vs Book-1 §10.1 — SOx emissions arise mainly from the sulphur content of oil and coal; natural gas is essentially sulphur-free, so switching from furnace oil to natural gas decreases SO2. CO2 also falls (§10.5: 'for the same amount of heat released, natural gas emits the least CO2'), and wet flue gas loss actually increases with gas firing because of its higher hydrogen content.
📖 §3.4 The laws of thermodynamics

32. The law of conservation of energy states that energy

  1. can be created and destroyed
  2. is destroyed in the process of burning
  3. cannot be converted from one form to another
  4. is neither destroyed nor created
Answer: D) is neither destroyed nor created
Confirmed vs Book-1 §3.4 — Energy is neither created nor destroyed, only transformed. (Answer not marked in source.). Book-1 Ch.3, The laws of thermodynamics.
📖 §3.4 Latent heat of fusion / vaporization — Qₗ = m · h

33. Latent heat is best described as the amount of heat required to cause a change in

  1. both temperature and state
  2. specific heat
  3. state without a change in temperature
  4. temperature without a change in state
Answer: C) state without a change in temperature
Confirmed vs Book-1 §3.4 — Latent heat changes the state at constant temperature. (Answer not marked in source.). Book-1 Ch.3, Latent heat of fusion / vaporization — Qₗ = m · h.
📖 §3.4 Heat transfer — conduction, convection, radiation (rate in Watts)

34. When heat flows from one place to another by means of liquid or gas, it is being transferred by

  1. radiation
  2. conduction
  3. sublimation
  4. convection
Answer: D) convection
Confirmed vs Book-1 §3.4 — Heat transfer by movement of a fluid is convection. (Answer not marked in source.). Book-1 Ch.3, Heat transfer — conduction, convection, radiation (rate in Watts).
📖 §3.5 Energy units and conversions

35. How many Watts are equivalent to one HP?

  1. 760
  2. 725
  3. 740
  4. 746
Answer: D) 746
Confirmed vs Book-1 §3.5 — 1 HP = 746 W. (Answer not marked in source.). Book-1 Ch.3, Energy units and conversions.
📖 §9.6 Specific Energy Consumption — units

36. Which of the following terms does not refer to specific energy consumption?

  1. kWh/ton
  2. kCal/ton
  3. kJ/kg
  4. kg/kCal
Answer: D) kg/kCal
Confirmed vs Book-1 §9.6 — SEC is always ENERGY per unit of OUTPUT: kWh/ton, kCal/ton and kJ/kg are all valid SEC units. kg/kCal is output per unit energy (the inverse), so it is not a specific energy consumption unit. Answer (d).
📖 §10.4 Ozone layer depletion

37. The Ozone layer is found in

  1. stratosphere
  2. atmosphere
  3. ionosphere
  4. troposphere
Answer: A) stratosphere
Confirmed vs Book-1 §10.4 — 'Ozone layer is a thin layer of ozone (O3) present in stratosphere which extends from 10–50 km from the earth.' The troposphere is the lower layer where weather occurs and holds 90% of atmospheric molecules.
📖 §3.4 Calorific value — GCV vs NCV (bomb calorimeter)

38. A process requires 100 kg of fuel with a calorific value of 5000 kCal/kg. If the system efficiency is 80%, then the losses would be

  1. 100000 kCal
  2. 400000 kCal
  3. 50000 kCal
  4. 20000 kCal
Answer: A) 100000 kCal
Confirmed vs Book-1 §3.4 — Input = 100 x 5000 = 500,000 kCal; losses = 20% = 100,000 kCal. (Answer not marked in source.). Book-1 Ch.3, Calorific value — GCV vs NCV (bomb calorimeter).
📖 §10.4 Chemistry of ozone depletion

39. Ozone depletion process is due to

  1. carbon dioxide
  2. UV light breaking the ozone
  3. nitrogen
  4. chlorine atoms destroying ozone molecules
Answer: D) chlorine atoms destroying ozone molecules
Confirmed vs Book-1 §10.4 — 'It is the chlorine and bromine atom that actually destroys ozone, not the intact ODS molecule.' UV radiation only breaks the CFC molecule apart to release the chlorine atom; the chlorine then strips an oxygen from O3, forming O2 and ClO, and is regenerated to repeat the cycle.
📖 §1.7 Indian Energy Scenario — Electrical Energy Supply (thermal cycle)

40. The major share of energy loss in a thermal power plant is in the

  1. generator
  2. boiler
  3. condenser
  4. turbine
Answer: C) condenser
Confirmed — in a Rankine-cycle thermal station the single biggest energy loss is the latent heat rejected to cooling water in the condenser (roughly half the fuel energy). Boiler losses (flue gas, radiation) are much smaller, and turbine/generator losses are only a few percent, so the condenser is the correct choice.
📖 §11.1 Concept of New and Renewable Energy (Concept of renewable energy)

41. Which of the following is a renewable energy source?

  1. bitumen
  2. bagasse
  3. Diesel oil
  4. natural gas
Answer: B) bagasse
Confirmed vs Book-1 §11.1 Concept of New and Renewable Energy (Concept of renewable energy) — The book lists renewable sources as sun, wind, falling water, sea waves, geothermal heat and biomass; solid biomass explicitly includes bagasse (§11.6, Direct Combustion of Biomass). Bitumen, diesel oil and natural gas are all fossil (stock) fuels. Answer b.
📖 §7.3 Financial Analysis Techniques — Internal Rate of Return Method

42. Which of the following is not true of IRR?

  1. it takes into account time value of money
  2. it considers the cash flow streams in its entirety
  3. does not distinguish between lending and borrowing
  4. none of the above
Answer: D) none of the above
Confirmed vs Book-1 §7.3 — Book lists as IRR advantages: it takes account of the time value of money and considers the cash-flow stream in its entirety - so (a) and (b) are true. Its stated limitation is that 'the internal rate of return figure cannot distinguish between lending and borrowing' - so (c) is also true of IRR. All three statements are true, hence 'none of the above' is the statement that is NOT true.
📖 §6.4 Energy Policy and Planning - Force Field Analysis

43. An analysis which helps to bring into focus the negative and positive forces in an organization is

  1. energy action planning
  2. force field analysis
  3. energy policy
  4. energy analysis
Answer: B) force field analysis
Confirmed vs Book-1 §6.4 Energy Policy and Planning — Force field analysis is the tool the guidebook prescribes before creating an action plan: it identifies the positive (driving) forces working towards the goal and the negative (barrier) forces working against it. Energy action planning (a) is the whole six-step process, and an energy policy (c) is a written declaration of commitment - neither is an analytical technique for weighing opposing forces.
📖 §3.3 Power factor — power triangle kW/kVA/kVAr, PF = cosθ

44. The lagging reactive power is required for

  1. inductive load
  2. resistive load
  3. capacitive load
  4. all of the above
Answer: A) inductive load
Confirmed vs Book-1 §3.3 — Inductive loads draw lagging reactive power. (Answer not marked in source.). Book-1 Ch.3, Power factor — power triangle kW/kVA/kVAr, PF = cosθ.
📖 §10.11 Small-scale CDM (fast track)

45. Fast track approval procedures for CDM projects are applicable to renewable energy projects with output capacity up to

  1. 5 MW
  2. 10 MW
  3. 15 MW
  4. 20 MW
Answer: C) 15 MW
Confirmed vs Book-1 §10.11 — Small-scale project Type I = renewable energy projects with a capacity of up to 15 MW; Type II = energy-efficiency projects saving up to 15 GWh/year (54 TJ); Type III = other projects emitting less than 15 kt CO2/year.
📖 §1.7 Indian Energy Scenario — Electrical Energy Supply (station heat rate)

46. The performance parameter for thermal power station is

  1. kWh/kCal
  2. kCal/kWh
  3. kWh/MT
  4. kCal/kg
Answer: B) kCal/kWh
Confirmed — the performance yardstick of a thermal power station is the heat rate, the heat input required per unit of electricity generated, expressed in kCal/kWh. Its inverse (kWh/kCal) is not used, and kCal/kg is a fuel calorific value, not a station performance figure.
📖 §9.6 Normalisation of data

47. The process of removing the impact of various factors on energy use so that energy performance of facilities and operations can be compared is called

  1. Averaging
  2. Normalization
  3. Tracking
  4. Optimization
Answer: B) Normalization
Confirmed vs Book-1 §9.6 — removing the influence of variable factors (production level, weather/degree-days, occupancy, product mix) so that facilities and periods can be fairly compared is called normalisation. Regression/production-factor methods in M&T are the normalising tools. Answer (b).

Short questions (5 marks) — 5

📖 §4.12 Energy audit instruments and metering

1. Name the instrument used to measure each of the following in an energy audit: (a) O₂, CO, CO₂ and temperature in flue gas; (b) Illumination levels; (c) Non-contact speed measurement; (d) kW, kWh, kVAr, kVA and power factor; (e) Non-contact surface temperature.

Model answer: (a) Combustion (flue gas) analyser; (b) Lux meter; (c) Stroboscope; (d) Power analyser; (e) Non-contact infrared (IR) thermometer.
This is the reverse question - parameter given, instrument wanted. Answer with the instrument name only, one line each. The giveaway in (a) is CO. The moment CO appears, the answer is a combustion (flue gas) ANALYSER, never a Fyrite - the Fyrite cannot read CO. In (c) "non-contact speed" means stroboscope; if it had said contact, the answer would be tachometer. In (e) "non-contact temperature" means infrared thermometer; a contact thermometer is a thermocouple probe. For (d), the single instrument covering kW, kWh, kVA, kVAr and PF together is the power analyser (clamp-on type is applied on-line without stopping the motor).
📖 §9.6 Fixed energy from E = M·P + C

2. Calculate the fixed energy consumption for a rolling mill consuming 1,00,000 units of electricity to produce 600 MT/month with a specific energy consumption of 100 kWh/MT.

Model answer: Total energy = Fixed energy + (SEC x production), i.e. E = c + mP. Therefore fixed energy c = Total - (SEC x production) = 1,00,000 - (100 x 600) = 1,00,000 - 60,000 = 40,000 units. The variable (production-related) energy is 60,000 units and the fixed/base-load energy is 40,000 units.
Applies the Ch9 relation E = c + mP. Past-paper numeric, not in OCR body, so verified=false.
📖 §9.2/§9.6 Normalising of data & benchmarking

3. What is meant by (a) Normalising of data and (b) Benchmarking?

Model answer: (a) Normalising of data is the process of removing the impact of variable factors (such as weather/degree-days, production level, occupancy, operating characteristics) on energy use so that energy performance can be compared on a like-for-like basis and a meaningful baseline established. (Note: maintenance cost is NOT a normalising factor.) (b) Benchmarking is the comparison of one's energy performance against that of peers, competitors or similar organisations to establish a relative understanding of where one's performance ranks, and to set realistic external targets.
Concept consistent with Ch9 (targeting uses benchmarking with similar organisations); definitions are standard. Not verbatim in OCR -> verified=false.
📖 §7.5 Sensitivity Analysis — micro vs macro factors

4. In financial management, what are micro and macro factors? List three of each that influence sensitivity analysis.

Model answer: Micro factors are variables related to the project that the firm CAN influence/change: e.g. operating expenses, capital structure, cost of debt/equity, changing the form of finance (e.g. leasing), changing the project life. Macro factors are macro-economic variables affecting the whole industry that the firm's management CANNOT change: e.g. changes in interest rates, changes in tax rates, changes in accounting standards / depreciation methods and rates, government subsidies, employment/salary trends, environmental & safety regulations, energy price changes, technology changes.
Micro = firm-controllable; Macro = external/uncontrollable.
📖 §10.3 Acid Rain

5. Write short notes on the causes of acid rain and its effects.

Model answer: Causes: Acid rain is caused by release of sulphur oxides (SOx) and nitrogen oxides (NOx) from combustion of fossil fuels, which mix with water vapour in the atmosphere to form sulphuric acid (H2SO4) and nitric acid (HNO3) respectively. It is a trans-boundary issue and deposits as wet deposition (rain, snow, sleet) and dry deposition (particulates, gases). Effects: acidification of lakes, streams and soils; direct and indirect effects (release of metals such as aluminium which wash away plant nutrients); killing of wildlife (trees, crops, aquatic plants and animals); decay of building materials, paints, statues and sculptures; and health problems (respiratory, burning skin and eyes).
Fix the two pairs: SOx + water vapour = sulphuric acid (H2SO4), NOx + water vapour = nitric acid (HNO3). Write both forms of deposition - WET (rain, snow, sleet) and DRY (particulates, gases) - many students give only wet. The word "trans-boundary" is worth writing: the acid falls in a country that did not emit it. Split your answer clearly into Causes and Effects, since the question asks for both.